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61026214553 = 137594435367
BaseRepresentation
bin111000110101011100…
…100010001010011001
312211112000120220110122
4320311130202022121
51444440202331203
644011323323025
74260200156603
oct706534421231
9184460526418
1061026214553
1123976786267
12b9b1680475
1359a7245335
142d4cca6173
1518c28b1538
hexe35722299

61026214553 has 4 divisors (see below), whose sum is σ = 61030663680. Its totient is φ = 61021765428.

The previous prime is 61026214549. The next prime is 61026214597. The reversal of 61026214553 is 35541262016.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 61026214553 - 22 = 61026214549 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (61026214853) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2203925 + ... + 2231442.

It is an arithmetic number, because the mean of its divisors is an integer number (15257665920).

Almost surely, 261026214553 is an apocalyptic number.

It is an amenable number.

61026214553 is a deficient number, since it is larger than the sum of its proper divisors (4449127).

61026214553 is a wasteful number, since it uses less digits than its factorization.

61026214553 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4449126.

The product of its (nonzero) digits is 43200, while the sum is 35.

Adding to 61026214553 its reverse (35541262016), we get a palindrome (96567476569).

The spelling of 61026214553 in words is "sixty-one billion, twenty-six million, two hundred fourteen thousand, five hundred fifty-three".

Divisors: 1 13759 4435367 61026214553