61042133124017 has 2 divisors, whose sum is σ = 61042133124018. Its totient is φ = 61042133124016.

The previous prime is 61042133123981. The next prime is 61042133124067. The reversal of 61042133124017 is 71042133124016.

61042133124017 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 56505228864016 + 4536904260001 = 7516996^2 + 2130001^2 .

It is a cyclic number.

It is not a de Polignac number, because 61042133124017 - 2¹⁸ = 61042132861873 is a prime.

It is a super-2 number, since 2×61042133124017² (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (61042133124067) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30521066562008 + 30521066562009.

It is an arithmetic number, because the mean of its divisors is an integer number (30521066562009).

Almost surely, 2^{61042133124017} is an apocalyptic number.

It is an amenable number.

61042133124017 is a deficient number, since it is larger than the sum of its proper divisors (1).

61042133124017 is an equidigital number, since it uses as much as digits as its factorization.

61042133124017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24192, while the sum is 35.

Subtracting 61042133124017 from its reverse (71042133124016), we obtain a palindrome (9999999999999).

The spelling of 61042133124017 in words is "sixty-one trillion, forty-two billion, one hundred thirty-three million, one hundred twenty-four thousand, seventeen".