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61043000354345 = 512208600070869
BaseRepresentation
bin11011110000100101011100…
…10110100010011000101001
322000010122122122120021100202
431320102232112202120221
531000112031042314340
6333454433415441545
715600132311605142
oct1570225626423051
9260118578507322
1061043000354345
11184a5211348729
126a1a6613862b5
13280a43a6a6189
1411106d5a06ac9
1570cd06414c15
hex3784ae5a2629

61043000354345 has 4 divisors (see below), whose sum is σ = 73251600425220. Its totient is φ = 48834400283472.

The previous prime is 61043000354311. The next prime is 61043000354353. The reversal of 61043000354345 is 54345300034016.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 14113636403344 + 46929363951001 = 3756812^2 + 6850501^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-61043000354345 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 61043000354299 and 61043000354308.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6104300035430 + ... + 6104300035439.

It is an arithmetic number, because the mean of its divisors is an integer number (18312900106305).

Almost surely, 261043000354345 is an apocalyptic number.

It is an amenable number.

61043000354345 is a deficient number, since it is larger than the sum of its proper divisors (12208600070875).

61043000354345 is a wasteful number, since it uses less digits than its factorization.

61043000354345 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12208600070874.

The product of its (nonzero) digits is 259200, while the sum is 38.

The spelling of 61043000354345 in words is "sixty-one trillion, forty-three billion, three hundred fifty-four thousand, three hundred forty-five".

Divisors: 1 5 12208600070869 61043000354345