Base | Representation |
---|---|
bin | 101100011101001100010… |
… | …1011100011101010101111 |
3 | 210122002222202110002121111 |
4 | 1120322120223203222233 |
5 | 1300101242243100111 |
6 | 20554521513012451 |
7 | 1200301423003561 |
oct | 130723053435257 |
9 | 23562882402544 |
10 | 6110005050031 |
11 | 1a46269621743 |
12 | 8281b03b4127 |
13 | 35422b90748c |
14 | 171a23929331 |
15 | a8e0672ba21 |
hex | 58e98ae3aaf |
6110005050031 has 2 divisors, whose sum is σ = 6110005050032. Its totient is φ = 6110005050030.
The previous prime is 6110005050011. The next prime is 6110005050041. The reversal of 6110005050031 is 1300505000116.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-6110005050031 is a prime.
It is a super-2 number, since 2×61100050500312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 6110005049984 and 6110005050011.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (6110005050001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3055002525015 + 3055002525016.
It is an arithmetic number, because the mean of its divisors is an integer number (3055002525016).
Almost surely, 26110005050031 is an apocalyptic number.
6110005050031 is a deficient number, since it is larger than the sum of its proper divisors (1).
6110005050031 is an equidigital number, since it uses as much as digits as its factorization.
6110005050031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 450, while the sum is 22.
The spelling of 6110005050031 in words is "six trillion, one hundred ten billion, five million, fifty thousand, thirty-one".
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