Base | Representation |
---|---|
bin | 1110100100100… |
… | …0001100101011 |
3 | 11020222212110022 |
4 | 3221020030223 |
5 | 111121110011 |
6 | 10021511055 |
7 | 1341311252 |
oct | 351101453 |
9 | 136885408 |
10 | 61113131 |
11 | 31551222 |
12 | 1857248b |
13 | c879821 |
14 | 818b799 |
15 | 55728db |
hex | 3a4832b |
61113131 has 2 divisors, whose sum is σ = 61113132. Its totient is φ = 61113130.
The previous prime is 61113103. The next prime is 61113161. The reversal of 61113131 is 13131116.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 61113131 - 214 = 61096747 is a prime.
It is a super-2 number, since 2×611131312 = 7469629561246322, which contains 22 as substring.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (61113161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30556565 + 30556566.
It is an arithmetic number, because the mean of its divisors is an integer number (30556566).
Almost surely, 261113131 is an apocalyptic number.
61113131 is a deficient number, since it is larger than the sum of its proper divisors (1).
61113131 is an equidigital number, since it uses as much as digits as its factorization.
61113131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 54, while the sum is 17.
The square root of 61113131 is about 7817.4887911656. The cubic root of 61113131 is about 393.8929231387.
Adding to 61113131 its reverse (13131116), we get a palindrome (74244247).
The spelling of 61113131 in words is "sixty-one million, one hundred thirteen thousand, one hundred thirty-one".
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