Base | Representation |
---|---|
bin | 11011110010101000010100… |
… | …01010110100111101010101 |
3 | 22000101101000011222120001001 |
4 | 31321110022022310331111 |
5 | 31002234424111442201 |
6 | 333551013313303301 |
7 | 15605200363155526 |
oct | 1571241212647525 |
9 | 260341004876031 |
10 | 61113260265301 |
11 | 18521a96222742 |
12 | 6a301ab264b31 |
13 | 2813c5692339a |
14 | 1113c7cd5884d |
15 | 70ea69766301 |
hex | 37950a2b4f55 |
61113260265301 has 2 divisors, whose sum is σ = 61113260265302. Its totient is φ = 61113260265300.
The previous prime is 61113260265289. The next prime is 61113260265307. The reversal of 61113260265301 is 10356206231116.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 57415081271076 + 3698178994225 = 7577274^2 + 1923065^2 .
It is a cyclic number.
It is not a de Polignac number, because 61113260265301 - 213 = 61113260257109 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (61113260265307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30556630132650 + 30556630132651.
It is an arithmetic number, because the mean of its divisors is an integer number (30556630132651).
Almost surely, 261113260265301 is an apocalyptic number.
It is an amenable number.
61113260265301 is a deficient number, since it is larger than the sum of its proper divisors (1).
61113260265301 is an equidigital number, since it uses as much as digits as its factorization.
61113260265301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 38880, while the sum is 37.
Adding to 61113260265301 its reverse (10356206231116), we get a palindrome (71469466496417).
The spelling of 61113260265301 in words is "sixty-one trillion, one hundred thirteen billion, two hundred sixty million, two hundred sixty-five thousand, three hundred one".
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