Base | Representation |
---|---|
bin | 10001110010011001011… |
… | …01101100101101001011 |
3 | 2011102112122200222121120 |
4 | 20321030231230231023 |
5 | 40003140113412133 |
6 | 1144434013410323 |
7 | 62104264501365 |
oct | 10711455545513 |
9 | 2142478628546 |
10 | 611172404043 |
11 | 216218986073 |
12 | 9a5484999a3 |
13 | 458304c9486 |
14 | 2181bdd1d35 |
15 | 10d70b14ab3 |
hex | 8e4cb6cb4b |
611172404043 has 8 divisors (see below), whose sum is σ = 815175911568. Its totient is φ = 407308582944.
The previous prime is 611172404033. The next prime is 611172404047. The reversal of 611172404043 is 340404271116.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 611172404043 - 26 = 611172403979 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 611172403995 and 611172404013.
It is not an unprimeable number, because it can be changed into a prime (611172404047) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 34911396 + ... + 34928897.
It is an arithmetic number, because the mean of its divisors is an integer number (101896988946).
Almost surely, 2611172404043 is an apocalyptic number.
611172404043 is a deficient number, since it is larger than the sum of its proper divisors (204003507525).
611172404043 is a wasteful number, since it uses less digits than its factorization.
611172404043 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 69843213.
The product of its (nonzero) digits is 16128, while the sum is 33.
Adding to 611172404043 its reverse (340404271116), we get a palindrome (951576675159).
The spelling of 611172404043 in words is "six hundred eleven billion, one hundred seventy-two million, four hundred four thousand, forty-three".
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