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6112050202513 is a prime number
BaseRepresentation
bin101100011110001001010…
…0101001100011110010001
3210122022021021202121101201
41120330102211030132101
51300114434322440023
620555500451431201
71200403205343343
oct130742245143621
923568237677351
106112050202513
111a47118aa9002
128286812b5501
13354496530688
14171b793b9293
15a8ec605cbad
hex58f1294c791

6112050202513 has 2 divisors, whose sum is σ = 6112050202514. Its totient is φ = 6112050202512.

The previous prime is 6112050202499. The next prime is 6112050202543. The reversal of 6112050202513 is 3152020502116.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4173918462289 + 1938131740224 = 2043017^2 + 1392168^2 .

It is a cyclic number.

It is not a de Polignac number, because 6112050202513 - 237 = 5974611249041 is a prime.

It is not a weakly prime, because it can be changed into another prime (6112050202543) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3056025101256 + 3056025101257.

It is an arithmetic number, because the mean of its divisors is an integer number (3056025101257).

Almost surely, 26112050202513 is an apocalyptic number.

It is an amenable number.

6112050202513 is a deficient number, since it is larger than the sum of its proper divisors (1).

6112050202513 is an equidigital number, since it uses as much as digits as its factorization.

6112050202513 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3600, while the sum is 28.

Adding to 6112050202513 its reverse (3152020502116), we get a palindrome (9264070704629).

The spelling of 6112050202513 in words is "six trillion, one hundred twelve billion, fifty million, two hundred two thousand, five hundred thirteen".