Base | Representation |
---|---|
bin | 101100011110001001010… |
… | …0101001100011110101111 |
3 | 210122022021021202121102211 |
4 | 1120330102211030132233 |
5 | 1300114434322440133 |
6 | 20555500451431251 |
7 | 1200403205343415 |
oct | 130742245143657 |
9 | 23568237677384 |
10 | 6112050202543 |
11 | 1a47118aa902a |
12 | 8286812b5527 |
13 | 3544965306ac |
14 | 171b793b92b5 |
15 | a8ec605cbcd |
hex | 58f1294c7af |
6112050202543 has 2 divisors, whose sum is σ = 6112050202544. Its totient is φ = 6112050202542.
The previous prime is 6112050202513. The next prime is 6112050202567. The reversal of 6112050202543 is 3452020502116.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 6112050202543 - 29 = 6112050202031 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (6112050202513) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3056025101271 + 3056025101272.
It is an arithmetic number, because the mean of its divisors is an integer number (3056025101272).
Almost surely, 26112050202543 is an apocalyptic number.
6112050202543 is a deficient number, since it is larger than the sum of its proper divisors (1).
6112050202543 is an equidigital number, since it uses as much as digits as its factorization.
6112050202543 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 6112050202543 its reverse (3452020502116), we get a palindrome (9564070704659).
The spelling of 6112050202543 in words is "six trillion, one hundred twelve billion, fifty million, two hundred two thousand, five hundred forty-three".
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