61131041553 has 4 divisors (see below), whose sum is σ = 81508055408. Its totient is φ = 40754027700.

The previous prime is 61131041501. The next prime is 61131041561. The reversal of 61131041553 is 35514013116.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 61131041553 - 2⁸ = 61131041297 is a prime.

It is a super-2 number, since 2×61131041553² (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 61131041553.

It is not an unprimeable number, because it can be changed into a prime (61131041563) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10188506923 + ... + 10188506928.

It is an arithmetic number, because the mean of its divisors is an integer number (20377013852).

Almost surely, 2^61131041553 is an apocalyptic number.

It is an amenable number.

61131041553 is a deficient number, since it is larger than the sum of its proper divisors (20377013855).

61131041553 is a wasteful number, since it uses less digits than its factorization.

61131041553 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20377013854.

The product of its (nonzero) digits is 5400, while the sum is 30.

Adding to 61131041553 its reverse (35514013116), we get a palindrome (96645054669).

The spelling of 61131041553 in words is "sixty-one billion, one hundred thirty-one million, forty-one thousand, five hundred fifty-three".