Base | Representation |
---|---|
bin | 101100011110101000111… |
… | …1010100011100011101111 |
3 | 210122102000100011110102222 |
4 | 1120331101322203203233 |
5 | 1300124123332013303 |
6 | 21000154130105555 |
7 | 1200441430111205 |
oct | 130752172434357 |
9 | 23572010143388 |
10 | 6113112766703 |
11 | 1a47613874228 |
12 | 82891911b2bb |
13 | 354605704997 |
14 | 171c3a571075 |
15 | a903949b938 |
hex | 58f51ea38ef |
6113112766703 has 4 divisors (see below), whose sum is σ = 6262213078128. Its totient is φ = 5964012455280.
The previous prime is 6113112766699. The next prime is 6113112766757. The reversal of 6113112766703 is 3076672113116.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 6113112766703 - 22 = 6113112766699 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (6113112766763) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 74550155651 + ... + 74550155732.
It is an arithmetic number, because the mean of its divisors is an integer number (1565553269532).
Almost surely, 26113112766703 is an apocalyptic number.
6113112766703 is a deficient number, since it is larger than the sum of its proper divisors (149100311425).
6113112766703 is a wasteful number, since it uses less digits than its factorization.
6113112766703 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 149100311424.
The product of its (nonzero) digits is 190512, while the sum is 44.
Adding to 6113112766703 its reverse (3076672113116), we get a palindrome (9189784879819).
The spelling of 6113112766703 in words is "six trillion, one hundred thirteen billion, one hundred twelve million, seven hundred sixty-six thousand, seven hundred three".
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