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611315431 is a prime number
BaseRepresentation
bin100100011011111…
…110111011100111
31120121022001010021
4210123332323213
52222444043211
6140354340011
721102044506
oct4433767347
91517261107
10611315431
11294087371
1215088a607
139985b10c
145b29083d
1538a05771
hex246feee7

611315431 has 2 divisors, whose sum is σ = 611315432. Its totient is φ = 611315430.

The previous prime is 611315407. The next prime is 611315473. The reversal of 611315431 is 134513116.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 611315431 - 25 = 611315399 is a prime.

It is a super-2 number, since 2×6113154312 = 747413112357431522, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 611315396 and 611315405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (611319431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 305657715 + 305657716.

It is an arithmetic number, because the mean of its divisors is an integer number (305657716).

Almost surely, 2611315431 is an apocalyptic number.

611315431 is a deficient number, since it is larger than the sum of its proper divisors (1).

611315431 is an equidigital number, since it uses as much as digits as its factorization.

611315431 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1080, while the sum is 25.

The square root of 611315431 is about 24724.7938515167. The cubic root of 611315431 is about 848.7017926482.

Adding to 611315431 its reverse (134513116), we get a palindrome (745828547).

The spelling of 611315431 in words is "six hundred eleven million, three hundred fifteen thousand, four hundred thirty-one".