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61134145465333 is a prime number
BaseRepresentation
bin11011110011001111001110…
…00001100010101111110101
322000110100220201011122110011
431321213213001202233311
531003110212214342313
6334004345543500221
715606540054350533
oct1571474701425765
9260410821148404
1061134145465333
111852a933395636
126a34259757671
132815c04812105
141114ca0a27153
1571038d08893d
hex3799e7062bf5

61134145465333 has 2 divisors, whose sum is σ = 61134145465334. Its totient is φ = 61134145465332.

The previous prime is 61134145465249. The next prime is 61134145465343. The reversal of 61134145465333 is 33356454143116.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 60390647984164 + 743497481169 = 7771142^2 + 862263^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-61134145465333 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (61134145465343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30567072732666 + 30567072732667.

It is an arithmetic number, because the mean of its divisors is an integer number (30567072732667).

Almost surely, 261134145465333 is an apocalyptic number.

It is an amenable number.

61134145465333 is a deficient number, since it is larger than the sum of its proper divisors (1).

61134145465333 is an equidigital number, since it uses as much as digits as its factorization.

61134145465333 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4665600, while the sum is 49.

The spelling of 61134145465333 in words is "sixty-one trillion, one hundred thirty-four billion, one hundred forty-five million, four hundred sixty-five thousand, three hundred thirty-three".