Base | Representation |
---|---|
bin | 111000111011111101… |
… | …010001101010100111 |
3 | 12211210122011012110111 |
4 | 320323331101222213 |
5 | 2000201134223111 |
6 | 44030225033451 |
7 | 4262664562501 |
oct | 707375215247 |
9 | 184718135414 |
10 | 61135461031 |
11 | 23a22412807 |
12 | ba22185887 |
13 | 59c3a75718 |
14 | 2d5d5c2d71 |
15 | 18cc290a21 |
hex | e3bf51aa7 |
61135461031 has 4 divisors (see below), whose sum is σ = 61138036872. Its totient is φ = 61132885192.
The previous prime is 61135460993. The next prime is 61135461103. The reversal of 61135461031 is 13016453116.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 61135461031 - 213 = 61135452839 is a prime.
It is a super-2 number, since 2×611354610312 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 61135460984 and 61135461002.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (61135461731) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1251985 + ... + 1299898.
It is an arithmetic number, because the mean of its divisors is an integer number (15284509218).
Almost surely, 261135461031 is an apocalyptic number.
61135461031 is a deficient number, since it is larger than the sum of its proper divisors (2575841).
61135461031 is a wasteful number, since it uses less digits than its factorization.
61135461031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2575840.
The product of its (nonzero) digits is 6480, while the sum is 31.
The spelling of 61135461031 in words is "sixty-one billion, one hundred thirty-five million, four hundred sixty-one thousand, thirty-one".
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