611403105497 has 2 divisors, whose sum is σ = 611403105498. Its totient is φ = 611403105496.

The previous prime is 611403105437. The next prime is 611403105499. The reversal of 611403105497 is 794501304116.

611403105497 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 594840445081 + 16562660416 = 771259^2 + 128696^2 .

It is a cyclic number.

It is not a de Polignac number, because 611403105497 - 2¹⁸ = 611402843353 is a prime.

It is a super-2 number, since 2×611403105497² (a number of 24 digits) contains 22 as substring.

Together with 611403105499, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (611403105499) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 305701552748 + 305701552749.

It is an arithmetic number, because the mean of its divisors is an integer number (305701552749).

Almost surely, 2^611403105497 is an apocalyptic number.

It is an amenable number.

611403105497 is a deficient number, since it is larger than the sum of its proper divisors (1).

611403105497 is an equidigital number, since it uses as much as digits as its factorization.

611403105497 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 90720, while the sum is 41.

The spelling of 611403105497 in words is "six hundred eleven billion, four hundred three million, one hundred five thousand, four hundred ninety-seven".