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6114117 = 32038039
BaseRepresentation
bin10111010100101101000101
3102111121222210
4113110231011
53031122432
6335014033
7102653262
oct27245505
912447883
106114117
1134a6699
12206a319
131360c29
14b52269
1580b8cc
hex5d4b45

6114117 has 4 divisors (see below), whose sum is σ = 8152160. Its totient is φ = 4076076.

The previous prime is 6114083. The next prime is 6114149. The reversal of 6114117 is 7114116.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a de Polignac number, because none of the positive numbers 2k-6114117 is a prime.

It is a D-number.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 6114093 and 6114102.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (6114167) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1019017 + ... + 1019022.

It is an arithmetic number, because the mean of its divisors is an integer number (2038040).

Almost surely, 26114117 is an apocalyptic number.

It is an amenable number.

6114117 is a deficient number, since it is larger than the sum of its proper divisors (2038043).

6114117 is a wasteful number, since it uses less digits than its factorization.

6114117 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2038042.

The product of its digits is 168, while the sum is 21.

The square root of 6114117 is about 2472.6740585852. The cubic root of 6114117 is about 182.8568560205.

Subtracting 6114117 from its reverse (7114116), we obtain a palindrome (999999).

The spelling of 6114117 in words is "six million, one hundred fourteen thousand, one hundred seventeen".

Divisors: 1 3 2038039 6114117