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611425210013 is a prime number
BaseRepresentation
bin10001110010110111100…
…10000100111010011101
32011110012021101212012122
420321123302010322131
540004144323210023
61144515044112325
762113454351132
oct10713362047235
92143167355178
10611425210013
11216338655a22
129a5b90956a5
13458709b20c7
14218437dc589
1510d87e002c8
hex8e5bc84e9d

611425210013 has 2 divisors, whose sum is σ = 611425210014. Its totient is φ = 611425210012.

The previous prime is 611425209977. The next prime is 611425210021. The reversal of 611425210013 is 310012524116.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 610731309049 + 693900964 = 781493^2 + 26342^2 .

It is a cyclic number.

It is not a de Polignac number, because 611425210013 - 218 = 611424947869 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (611425210043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 305712605006 + 305712605007.

It is an arithmetic number, because the mean of its divisors is an integer number (305712605007).

Almost surely, 2611425210013 is an apocalyptic number.

It is an amenable number.

611425210013 is a deficient number, since it is larger than the sum of its proper divisors (1).

611425210013 is an equidigital number, since it uses as much as digits as its factorization.

611425210013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 26.

Adding to 611425210013 its reverse (310012524116), we get a palindrome (921437734129).

The spelling of 611425210013 in words is "six hundred eleven billion, four hundred twenty-five million, two hundred ten thousand, thirteen".