Base | Representation |
---|---|
bin | 11011110011101010011110… |
… | …10111110101100111011111 |
3 | 22000111202200200120222111112 |
4 | 31321311033113311213133 |
5 | 31003330200421322033 |
6 | 334015210123012235 |
7 | 15610565540611634 |
oct | 1571651727654737 |
9 | 260452620528445 |
10 | 61148781042143 |
11 | 18536063831063 |
12 | 6a3706306a07b |
13 | 28173c79c5032 |
14 | 111588c6a818b |
15 | 710947db5c48 |
hex | 379d4f5f59df |
61148781042143 has 2 divisors, whose sum is σ = 61148781042144. Its totient is φ = 61148781042142.
The previous prime is 61148781042101. The next prime is 61148781042163. The reversal of 61148781042143 is 34124018784116.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-61148781042143 is a prime.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 61148781042091 and 61148781042100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (61148781042163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30574390521071 + 30574390521072.
It is an arithmetic number, because the mean of its divisors is an integer number (30574390521072).
Almost surely, 261148781042143 is an apocalyptic number.
61148781042143 is a deficient number, since it is larger than the sum of its proper divisors (1).
61148781042143 is an equidigital number, since it uses as much as digits as its factorization.
61148781042143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1032192, while the sum is 50.
The spelling of 61148781042143 in words is "sixty-one trillion, one hundred forty-eight billion, seven hundred eighty-one million, forty-two thousand, one hundred forty-three".
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