Base | Representation |
---|---|
bin | 111000111100110101… |
… | …010011111111111011 |
3 | 12211211122210111211111 |
4 | 320330311103333323 |
5 | 2000213414310101 |
6 | 44031511541151 |
7 | 4263233463412 |
oct | 707465237773 |
9 | 184748714744 |
10 | 61150150651 |
11 | 23a2a736297 |
12 | ba2708a7b7 |
13 | 59c6b199c5 |
14 | 2d61528479 |
15 | 18cd6e3251 |
hex | e3cd53ffb |
61150150651 has 2 divisors, whose sum is σ = 61150150652. Its totient is φ = 61150150650.
The previous prime is 61150150643. The next prime is 61150150673. The reversal of 61150150651 is 15605105116.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 61150150651 - 23 = 61150150643 is a prime.
It is a super-3 number, since 3×611501506513 (a number of 33 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (61150154651) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30575075325 + 30575075326.
It is an arithmetic number, because the mean of its divisors is an integer number (30575075326).
Almost surely, 261150150651 is an apocalyptic number.
61150150651 is a deficient number, since it is larger than the sum of its proper divisors (1).
61150150651 is an equidigital number, since it uses as much as digits as its factorization.
61150150651 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4500, while the sum is 31.
Adding to 61150150651 its reverse (15605105116), we get a palindrome (76755255767).
The spelling of 61150150651 in words is "sixty-one billion, one hundred fifty million, one hundred fifty thousand, six hundred fifty-one".
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