Base | Representation |
---|---|
bin | 101100100000100001000… |
… | …0110010010011101110001 |
3 | 210122210102011120201211012 |
4 | 1121001002012102131301 |
5 | 1300210401421434012 |
6 | 21002102034400305 |
7 | 1200643330160165 |
oct | 131010206223561 |
9 | 23583364521735 |
10 | 6117142374257 |
11 | 1a492a1440002 |
12 | 829662730095 |
13 | 354ac84c1855 |
14 | 1720dd7d0ca5 |
15 | a91c311e622 |
hex | 59042192771 |
6117142374257 has 4 divisors (see below), whose sum is σ = 6439097236080. Its totient is φ = 5795187512436.
The previous prime is 6117142374241. The next prime is 6117142374311. The reversal of 6117142374257 is 7524732417116.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 6117142374257 - 24 = 6117142374241 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (6117142374227) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 160977430883 + ... + 160977430920.
It is an arithmetic number, because the mean of its divisors is an integer number (1609774309020).
Almost surely, 26117142374257 is an apocalyptic number.
It is an amenable number.
6117142374257 is a deficient number, since it is larger than the sum of its proper divisors (321954861823).
6117142374257 is a wasteful number, since it uses less digits than its factorization.
6117142374257 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 321954861822.
The product of its digits is 1975680, while the sum is 50.
The spelling of 6117142374257 in words is "six trillion, one hundred seventeen billion, one hundred forty-two million, three hundred seventy-four thousand, two hundred fifty-seven".
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