Base | Representation |
---|---|
bin | 11011110110000010100111… |
… | …11000001100011001010111 |
3 | 22000210120112002212100021101 |
4 | 31323001103320030121113 |
5 | 31011144441004332133 |
6 | 334120515132130531 |
7 | 15616516622111335 |
oct | 1573012370143127 |
9 | 260716462770241 |
10 | 61230461011543 |
11 | 18567768a69aaa |
12 | 6a4aa59606a47 |
13 | 2822013bb2085 |
14 | 11197da5d2b55 |
15 | 712b28acd37d |
hex | 37b053e0c657 |
61230461011543 has 2 divisors, whose sum is σ = 61230461011544. Its totient is φ = 61230461011542.
The previous prime is 61230461011453. The next prime is 61230461011549. The reversal of 61230461011543 is 34511016403216.
Together with previous prime (61230461011453) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-61230461011543 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (61230461011549) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30615230505771 + 30615230505772.
It is an arithmetic number, because the mean of its divisors is an integer number (30615230505772).
Almost surely, 261230461011543 is an apocalyptic number.
61230461011543 is a deficient number, since it is larger than the sum of its proper divisors (1).
61230461011543 is an equidigital number, since it uses as much as digits as its factorization.
61230461011543 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 51840, while the sum is 37.
Adding to 61230461011543 its reverse (34511016403216), we get a palindrome (95741477414759).
The spelling of 61230461011543 in words is "sixty-one trillion, two hundred thirty billion, four hundred sixty-one million, eleven thousand, five hundred forty-three".
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