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612388402517 is a prime number
BaseRepresentation
bin10001110100101010011…
…00010111010101010101
32011112200101211002221002
420322111030113111111
540013132412340032
61145154412433045
762146361351423
oct10722514272525
92145611732832
10612388402517
11216792319791
129a827778785
13459954028b8
14218d56c8113
1510de2760862
hex8e95317555

612388402517 has 2 divisors, whose sum is σ = 612388402518. Its totient is φ = 612388402516.

The previous prime is 612388402441. The next prime is 612388402529. The reversal of 612388402517 is 715204883216.

612388402517 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 414960142276 + 197428260241 = 644174^2 + 444329^2 .

It is a cyclic number.

It is not a de Polignac number, because 612388402517 - 216 = 612388336981 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (612388402567) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 306194201258 + 306194201259.

It is an arithmetic number, because the mean of its divisors is an integer number (306194201259).

Almost surely, 2612388402517 is an apocalyptic number.

It is an amenable number.

612388402517 is a deficient number, since it is larger than the sum of its proper divisors (1).

612388402517 is an equidigital number, since it uses as much as digits as its factorization.

612388402517 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 645120, while the sum is 47.

The spelling of 612388402517 in words is "six hundred twelve billion, three hundred eighty-eight million, four hundred two thousand, five hundred seventeen".