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612514011141493 is a prime number
BaseRepresentation
bin1000101101000101000000100…
…0000011011101010101110101
32222022201202201120121201120121
42023101100020003131111311
51120240412143323011433
610010413015133131541
7243005451124013206
oct21321201003352565
92868652646551517
10612514011141493
1116819080809a21a
125884539b029bb1
13203a0a92057436
14ab37b9cc075ad
154ac2d65d05c2d
hex22d14080dd575

612514011141493 has 2 divisors, whose sum is σ = 612514011141494. Its totient is φ = 612514011141492.

The previous prime is 612514011141467. The next prime is 612514011141499. The reversal of 612514011141493 is 394141110415216.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 386537894761489 + 225976116380004 = 19660567^2 + 15032502^2 .

It is a cyclic number.

It is not a de Polignac number, because 612514011141493 - 29 = 612514011140981 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (612514011141499) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 306257005570746 + 306257005570747.

It is an arithmetic number, because the mean of its divisors is an integer number (306257005570747).

Almost surely, 2612514011141493 is an apocalyptic number.

It is an amenable number.

612514011141493 is a deficient number, since it is larger than the sum of its proper divisors (1).

612514011141493 is an equidigital number, since it uses as much as digits as its factorization.

612514011141493 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 103680, while the sum is 43.

The spelling of 612514011141493 in words is "six hundred twelve trillion, five hundred fourteen billion, eleven million, one hundred forty-one thousand, four hundred ninety-three".