Base | Representation |
---|---|
bin | 1011011010100100… |
… | …01011101001010011 |
3 | 120211002202112010111 |
4 | 11231102023221103 |
5 | 100022340401011 |
6 | 2452041542151 |
7 | 304603652356 |
oct | 55522135123 |
9 | 16732675114 |
10 | 6128450131 |
11 | 2665394321 |
12 | 12304a4957 |
13 | 768890c6b |
14 | 421cc829d |
15 | 25d05c121 |
hex | 16d48ba53 |
6128450131 has 2 divisors, whose sum is σ = 6128450132. Its totient is φ = 6128450130.
The previous prime is 6128450123. The next prime is 6128450137. The reversal of 6128450131 is 1310548216.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 6128450131 - 23 = 6128450123 is a prime.
It is a super-2 number, since 2×61284501312 = 75115802016307834322, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 6128450093 and 6128450102.
It is not a weakly prime, because it can be changed into another prime (6128450137) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3064225065 + 3064225066.
It is an arithmetic number, because the mean of its divisors is an integer number (3064225066).
Almost surely, 26128450131 is an apocalyptic number.
6128450131 is a deficient number, since it is larger than the sum of its proper divisors (1).
6128450131 is an equidigital number, since it uses as much as digits as its factorization.
6128450131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5760, while the sum is 31.
The square root of 6128450131 is about 78284.4181877850. The cubic root of 6128450131 is about 1829.9963302304.
Adding to 6128450131 its reverse (1310548216), we get a palindrome (7438998347).
The spelling of 6128450131 in words is "six billion, one hundred twenty-eight million, four hundred fifty thousand, one hundred thirty-one".
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