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6130049141 is a prime number
BaseRepresentation
bin1011011010110000…
…10010000001110101
3120211012202202120002
411231120102001311
5100023243033031
62452140121045
7304623362246
oct55530220165
916735682502
106130049141
112666286717
121230b36185
13769000a18
144221c2ccd
1525d275ccb
hex16d612075

6130049141 has 2 divisors, whose sum is σ = 6130049142. Its totient is φ = 6130049140.

The previous prime is 6130049131. The next prime is 6130049179. The reversal of 6130049141 is 1419400316.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3119222500 + 3010826641 = 55850^2 + 54871^2 .

It is a cyclic number.

It is not a de Polignac number, because 6130049141 - 210 = 6130048117 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (6130049131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3065024570 + 3065024571.

It is an arithmetic number, because the mean of its divisors is an integer number (3065024571).

Almost surely, 26130049141 is an apocalyptic number.

It is an amenable number.

6130049141 is a deficient number, since it is larger than the sum of its proper divisors (1).

6130049141 is an equidigital number, since it uses as much as digits as its factorization.

6130049141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 29.

The square root of 6130049141 is about 78294.6303458928. The cubic root of 6130049141 is about 1830.1554747618.

Adding to 6130049141 its reverse (1419400316), we get a palindrome (7549449457).

The spelling of 6130049141 in words is "six billion, one hundred thirty million, forty-nine thousand, one hundred forty-one".