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6130214120317 = 7875744874331
BaseRepresentation
bin101100100110100110100…
…1111000010101101111101
3210201001011011101020101011
41121031031033002231331
51300414134303322232
621012103111315221
71201615264163050
oct131151517025575
923631134336334
106130214120317
111a5389a069321
128300b037bb11
133560cc6c3a31
141729bd8b4a97
15a96da9e4547
hex5934d3c2b7d

6130214120317 has 4 divisors (see below), whose sum is σ = 7005958994656. Its totient is φ = 5254469245980.

The previous prime is 6130214120299. The next prime is 6130214120333. The reversal of 6130214120317 is 7130214120316.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 6130214120317 - 223 = 6130205731709 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (6130214120717) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 437872437159 + ... + 437872437172.

It is an arithmetic number, because the mean of its divisors is an integer number (1751489748664).

Almost surely, 26130214120317 is an apocalyptic number.

It is an amenable number.

6130214120317 is a deficient number, since it is larger than the sum of its proper divisors (875744874339).

6130214120317 is an equidigital number, since it uses as much as digits as its factorization.

6130214120317 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 875744874338.

The product of its (nonzero) digits is 6048, while the sum is 31.

Subtracting 6130214120317 from its reverse (7130214120316), we obtain a palindrome (999999999999).

The spelling of 6130214120317 in words is "six trillion, one hundred thirty billion, two hundred fourteen million, one hundred twenty thousand, three hundred seventeen".

Divisors: 1 7 875744874331 6130214120317