61309554011441 has 2 divisors, whose sum is σ = 61309554011442. Its totient is φ = 61309554011440.

The previous prime is 61309554011417. The next prime is 61309554011521. The reversal of 61309554011441 is 14411045590316.

61309554011441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 46958071939216 + 14351482072225 = 6852596^2 + 3788335^2 .

It is a cyclic number.

It is not a de Polignac number, because 61309554011441 - 2¹⁰ = 61309554010417 is a prime.

It is a super-2 number, since 2×61309554011441² (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 61309554011392 and 61309554011401.

It is not a weakly prime, because it can be changed into another prime (61309554011411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30654777005720 + 30654777005721.

It is an arithmetic number, because the mean of its divisors is an integer number (30654777005721).

Almost surely, 2^{61309554011441} is an apocalyptic number.

It is an amenable number.

61309554011441 is a deficient number, since it is larger than the sum of its proper divisors (1).

61309554011441 is an equidigital number, since it uses as much as digits as its factorization.

61309554011441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 259200, while the sum is 44.

The spelling of 61309554011441 in words is "sixty-one trillion, three hundred nine billion, five hundred fifty-four million, eleven thousand, four hundred forty-one".