Base | Representation |
---|---|
bin | 101100101000011011000… |
… | …0010111111111010011111 |
3 | 210201102020101002020200121 |
4 | 1121100312002333322133 |
5 | 1301000134213220211 |
6 | 21013550441135411 |
7 | 1202114133111055 |
oct | 131206602777237 |
9 | 23642211066617 |
10 | 6134120054431 |
11 | 1a55513944446 |
12 | 830a0048a567 |
13 | 3565a299b955 |
14 | 172c705401d5 |
15 | a9868888271 |
hex | 594360bfe9f |
6134120054431 has 2 divisors, whose sum is σ = 6134120054432. Its totient is φ = 6134120054430.
The previous prime is 6134120054399. The next prime is 6134120054453. The reversal of 6134120054431 is 1344500214316.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 6134120054431 - 25 = 6134120054399 is a prime.
It is a super-4 number, since 4×61341200544314 (a number of 52 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (6134120054131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3067060027215 + 3067060027216.
It is an arithmetic number, because the mean of its divisors is an integer number (3067060027216).
Almost surely, 26134120054431 is an apocalyptic number.
6134120054431 is a deficient number, since it is larger than the sum of its proper divisors (1).
6134120054431 is an equidigital number, since it uses as much as digits as its factorization.
6134120054431 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 34560, while the sum is 34.
Adding to 6134120054431 its reverse (1344500214316), we get a palindrome (7478620268747).
The spelling of 6134120054431 in words is "six trillion, one hundred thirty-four billion, one hundred twenty million, fifty-four thousand, four hundred thirty-one".
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