Base | Representation |
---|---|
bin | 111001001001000001… |
… | …101011111101110101 |
3 | 12212100220201202210022 |
4 | 321021001223331311 |
5 | 2001123302034031 |
6 | 44104100334525 |
7 | 4301266345010 |
oct | 711101537565 |
9 | 185326652708 |
10 | 61354721141 |
11 | 2402516010a |
12 | ba836a4445 |
13 | 5a2a31442c |
14 | 2d8077a377 |
15 | 18e165197b |
hex | e4906bf75 |
61354721141 has 4 divisors (see below), whose sum is σ = 70119681312. Its totient is φ = 52589760972.
The previous prime is 61354721117. The next prime is 61354721167. The reversal of 61354721141 is 14112745316.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 61354721141 - 210 = 61354720117 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (61354721101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4382480075 + ... + 4382480088.
It is an arithmetic number, because the mean of its divisors is an integer number (17529920328).
Almost surely, 261354721141 is an apocalyptic number.
It is an amenable number.
61354721141 is a deficient number, since it is larger than the sum of its proper divisors (8764960171).
61354721141 is an equidigital number, since it uses as much as digits as its factorization.
61354721141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8764960170.
The product of its digits is 20160, while the sum is 35.
The spelling of 61354721141 in words is "sixty-one billion, three hundred fifty-four million, seven hundred twenty-one thousand, one hundred forty-one".
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