61401104333533 has 8 divisors (see below), whose sum is σ = 63533467838880. Its totient is φ = 59269746431280.

The previous prime is 61401104333531. The next prime is 61401104333567. The reversal of 61401104333533 is 33533340110416.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 61401104333533 - 2¹ = 61401104333531 is a prime.

It is a super-2 number, since 2×61401104333533² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 61401104333492 and 61401104333501.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (61401104333531) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 251276535 + ... + 251520772.

It is an arithmetic number, because the mean of its divisors is an integer number (7941683479860).

Almost surely, 2^{61401104333533} is an apocalyptic number.

It is an amenable number.

61401104333533 is a deficient number, since it is larger than the sum of its proper divisors (2132363505347).

61401104333533 is a wasteful number, since it uses less digits than its factorization.

61401104333533 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 502801547.

The product of its (nonzero) digits is 116640, while the sum is 37.

Adding to 61401104333533 its reverse (33533340110416), we get a palindrome (94934444443949).

The spelling of 61401104333533 in words is "sixty-one trillion, four hundred one billion, one hundred four million, three hundred thirty-three thousand, five hundred thirty-three".