Base | Representation |
---|---|
bin | 11011111011000101001000… |
… | …11001001101000110100011 |
3 | 22001102010110012020110101221 |
4 | 31331202210121031012203 |
5 | 31022014043244044212 |
6 | 334332232415235511 |
7 | 15635156465553526 |
oct | 1575424431150643 |
9 | 261363405213357 |
10 | 61403610534307 |
11 | 186241413a3248 |
12 | 6a78520b18b97 |
13 | 28354494b32a2 |
14 | 1123d44674bbd |
15 | 7173aeba5807 |
hex | 37d8a464d1a3 |
61403610534307 has 2 divisors, whose sum is σ = 61403610534308. Its totient is φ = 61403610534306.
The previous prime is 61403610534193. The next prime is 61403610534373. The reversal of 61403610534307 is 70343501630416.
61403610534307 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 61403610534307 - 231 = 61401463050659 is a prime.
It is a super-3 number, since 3×614036105343073 (a number of 42 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (61403610534377) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30701805267153 + 30701805267154.
It is an arithmetic number, because the mean of its divisors is an integer number (30701805267154).
Almost surely, 261403610534307 is an apocalyptic number.
61403610534307 is a deficient number, since it is larger than the sum of its proper divisors (1).
61403610534307 is an equidigital number, since it uses as much as digits as its factorization.
61403610534307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 544320, while the sum is 43.
The spelling of 61403610534307 in words is "sixty-one trillion, four hundred three billion, six hundred ten million, five hundred thirty-four thousand, three hundred seven".
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