Base | Representation |
---|---|
bin | 111001001100011001… |
… | …001011101100010101 |
3 | 12212111212000210202022 |
4 | 321030121023230111 |
5 | 2001232232241203 |
6 | 44113435222525 |
7 | 4302553455362 |
oct | 711431135425 |
9 | 185455023668 |
10 | 61411212053 |
11 | 24054034614 |
12 | ba9a5a7a45 |
13 | 5a38c330c9 |
14 | 2d88083469 |
15 | 18e65aea38 |
hex | e4c64bb15 |
61411212053 has 2 divisors, whose sum is σ = 61411212054. Its totient is φ = 61411212052.
The previous prime is 61411212047. The next prime is 61411212157. The reversal of 61411212053 is 35021211416.
61411212053 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 59322447844 + 2088764209 = 243562^2 + 45703^2 .
It is a cyclic number.
It is not a de Polignac number, because 61411212053 - 214 = 61411195669 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (61411212013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30705606026 + 30705606027.
It is an arithmetic number, because the mean of its divisors is an integer number (30705606027).
Almost surely, 261411212053 is an apocalyptic number.
It is an amenable number.
61411212053 is a deficient number, since it is larger than the sum of its proper divisors (1).
61411212053 is an equidigital number, since it uses as much as digits as its factorization.
61411212053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 26.
Adding to 61411212053 its reverse (35021211416), we get a palindrome (96432423469).
It can be divided in two parts, 61 and 411212053, that added together give a palindrome (411212114).
The spelling of 61411212053 in words is "sixty-one billion, four hundred eleven million, two hundred twelve thousand, fifty-three".
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