Base | Representation |
---|---|
bin | 111001001110001111… |
… | …111110011111101101 |
3 | 12212121000121221021122 |
4 | 321032033332133231 |
5 | 2001313220300013 |
6 | 44120510510325 |
7 | 4303412245610 |
oct | 711617763755 |
9 | 185530557248 |
10 | 61442353133 |
11 | 2406a674347 |
12 | baa8b053a5 |
13 | 5a42517595 |
14 | 2d8c26c177 |
15 | 18e91b1a08 |
hex | e4e3fe7ed |
61442353133 has 4 divisors (see below), whose sum is σ = 70219832160. Its totient is φ = 52664874108.
The previous prime is 61442353129. The next prime is 61442353171. The reversal of 61442353133 is 33135324416.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 61442353133 - 22 = 61442353129 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 61442353093 and 61442353102.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (61442353103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4388739503 + ... + 4388739516.
It is an arithmetic number, because the mean of its divisors is an integer number (17554958040).
Almost surely, 261442353133 is an apocalyptic number.
It is an amenable number.
61442353133 is a deficient number, since it is larger than the sum of its proper divisors (8777479027).
61442353133 is an equidigital number, since it uses as much as digits as its factorization.
61442353133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8777479026.
The product of its digits is 77760, while the sum is 35.
Adding to 61442353133 its reverse (33135324416), we get a palindrome (94577677549).
The spelling of 61442353133 in words is "sixty-one billion, four hundred forty-two million, three hundred fifty-three thousand, one hundred thirty-three".
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