Base | Representation |
---|---|
bin | 101100101101100101101… |
… | …0000110000100100111011 |
3 | 210202110212111011122220021 |
4 | 1121123023100300210323 |
5 | 1301140344112321103 |
6 | 21023023322111311 |
7 | 1202656055026366 |
oct | 131331320604473 |
9 | 23673774148807 |
10 | 6145213401403 |
11 | 1a5a19683a19a |
12 | 832b9764b537 |
13 | 35765004a79b |
14 | 17360398d0dd |
15 | a9cb7715bbd |
hex | 596cb43093b |
6145213401403 has 8 divisors (see below), whose sum is σ = 6509415639888. Its totient is φ = 5781313284864.
The previous prime is 6145213401391. The next prime is 6145213401433. The reversal of 6145213401403 is 3041043125416.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 6145213401403 - 217 = 6145213270331 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (6145213401433) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 75488601 + ... + 75569962.
It is an arithmetic number, because the mean of its divisors is an integer number (813676954986).
Almost surely, 26145213401403 is an apocalyptic number.
6145213401403 is a deficient number, since it is larger than the sum of its proper divisors (364202238485).
6145213401403 is a wasteful number, since it uses less digits than its factorization.
6145213401403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 151060973.
The product of its (nonzero) digits is 34560, while the sum is 34.
Adding to 6145213401403 its reverse (3041043125416), we get a palindrome (9186256526819).
The spelling of 6145213401403 in words is "six trillion, one hundred forty-five billion, two hundred thirteen million, four hundred one thousand, four hundred three".
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