61471174893 has 4 divisors (see below), whose sum is σ = 81961566528. Its totient is φ = 40980783260.

The previous prime is 61471174883. The next prime is 61471175011. The reversal of 61471174893 is 39847117416.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 61471174893 - 2⁹ = 61471174381 is a prime.

It is a super-2 number, since 2×61471174893² (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (61471174883) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10245195813 + ... + 10245195818.

It is an arithmetic number, because the mean of its divisors is an integer number (20490391632).

Almost surely, 2^61471174893 is an apocalyptic number.

It is an amenable number.

61471174893 is a deficient number, since it is larger than the sum of its proper divisors (20490391635).

61471174893 is a wasteful number, since it uses less digits than its factorization.

61471174893 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20490391634.

The product of its digits is 1016064, while the sum is 51.

The spelling of 61471174893 in words is "sixty-one billion, four hundred seventy-one million, one hundred seventy-four thousand, eight hundred ninety-three".