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61491433 is a prime number
BaseRepresentation
bin1110101010010…
…0100011101001
311021201002101111
43222210203221
5111220211213
610033550321
71344445213
oct352444351
9137632344
1061491433
113178a473
12187153a1
13c97ca83
1482495b3
1555e9a3d
hex3aa48e9

61491433 has 2 divisors, whose sum is σ = 61491434. Its totient is φ = 61491432.

The previous prime is 61491427. The next prime is 61491457. The reversal of 61491433 is 33419416.

61491433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 48553024 + 12938409 = 6968^2 + 3597^2 .

It is a cyclic number.

It is not a de Polignac number, because 61491433 - 25 = 61491401 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 61491395 and 61491404.

It is not a weakly prime, because it can be changed into another prime (61491413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30745716 + 30745717.

It is an arithmetic number, because the mean of its divisors is an integer number (30745717).

Almost surely, 261491433 is an apocalyptic number.

It is an amenable number.

61491433 is a deficient number, since it is larger than the sum of its proper divisors (1).

61491433 is an equidigital number, since it uses as much as digits as its factorization.

61491433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 7776, while the sum is 31.

The square root of 61491433 is about 7841.6473396857. The cubic root of 61491433 is about 394.7040094164.

The spelling of 61491433 in words is "sixty-one million, four hundred ninety-one thousand, four hundred thirty-three".