Base | Representation |
---|---|
bin | 101100110000000001001… |
… | …1001101001100011010111 |
3 | 210202222100021121102001011 |
4 | 1121200002121221203113 |
5 | 1301232041430233403 |
6 | 21025245313513051 |
7 | 1203232321464532 |
oct | 131400231514327 |
9 | 23688307542034 |
10 | 6150433446103 |
11 | 1a61425380021 |
12 | 833bb3872787 |
13 | 357ca266122b |
14 | 17397ad6da19 |
15 | a9ec0b35a6d |
hex | 598026698d7 |
6150433446103 has 2 divisors, whose sum is σ = 6150433446104. Its totient is φ = 6150433446102.
The previous prime is 6150433445903. The next prime is 6150433446109. The reversal of 6150433446103 is 3016443340516.
6150433446103 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-6150433446103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (6150433446109) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3075216723051 + 3075216723052.
It is an arithmetic number, because the mean of its divisors is an integer number (3075216723052).
Almost surely, 26150433446103 is an apocalyptic number.
6150433446103 is a deficient number, since it is larger than the sum of its proper divisors (1).
6150433446103 is an equidigital number, since it uses as much as digits as its factorization.
6150433446103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 311040, while the sum is 40.
Adding to 6150433446103 its reverse (3016443340516), we get a palindrome (9166876786619).
The spelling of 6150433446103 in words is "six trillion, one hundred fifty billion, four hundred thirty-three million, four hundred forty-six thousand, one hundred three".
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