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61581330393953 is a prime number
BaseRepresentation
bin11100000000010000001010…
…10100101010101101100001
322002001010011210111202002212
432000020011110222231201
531032422031040101303
6334550023404451505
715654050526465236
oct1600100524525541
9262033153452085
1061581330393953
111869254a649207
126aa6a5ab49b95
13284912c916c56
14112c7a36d178d
1571bd12111ad8
hex38020552ab61

61581330393953 has 2 divisors, whose sum is σ = 61581330393954. Its totient is φ = 61581330393952.

The previous prime is 61581330393937. The next prime is 61581330393991. The reversal of 61581330393953 is 35939303318516.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 59978085680704 + 1603244713249 = 7744552^2 + 1266193^2 .

It is a cyclic number.

It is not a de Polignac number, because 61581330393953 - 24 = 61581330393937 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 61581330393892 and 61581330393901.

It is not a weakly prime, because it can be changed into another prime (61581330395953) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30790665196976 + 30790665196977.

It is an arithmetic number, because the mean of its divisors is an integer number (30790665196977).

Almost surely, 261581330393953 is an apocalyptic number.

It is an amenable number.

61581330393953 is a deficient number, since it is larger than the sum of its proper divisors (1).

61581330393953 is an equidigital number, since it uses as much as digits as its factorization.

61581330393953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 23619600, while the sum is 59.

The spelling of 61581330393953 in words is "sixty-one trillion, five hundred eighty-one billion, three hundred thirty million, three hundred ninety-three thousand, nine hundred fifty-three".