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617142584753 is a prime number
BaseRepresentation
bin10001111101100001001…
…00001000010110110001
32011222221201122120220122
420332300210020112301
540102402000203003
61151302243220025
762405240263142
oct10766044102661
92158851576818
10617142584753
1121880199a212
129b733977615
1346272354596
1421c26c7bac9
15110bed0c238
hex8fb09085b1

617142584753 has 2 divisors, whose sum is σ = 617142584754. Its totient is φ = 617142584752.

The previous prime is 617142584713. The next prime is 617142584759. The reversal of 617142584753 is 357485241716.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 371183125504 + 245959459249 = 609248^2 + 495943^2 .

It is a cyclic number.

It is not a de Polignac number, because 617142584753 - 28 = 617142584497 is a prime.

It is a super-2 number, since 2×6171425847532 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 617142584695 and 617142584704.

It is not a weakly prime, because it can be changed into another prime (617142584759) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 308571292376 + 308571292377.

It is an arithmetic number, because the mean of its divisors is an integer number (308571292377).

Almost surely, 2617142584753 is an apocalyptic number.

It is an amenable number.

617142584753 is a deficient number, since it is larger than the sum of its proper divisors (1).

617142584753 is an equidigital number, since it uses as much as digits as its factorization.

617142584753 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5644800, while the sum is 53.

The spelling of 617142584753 in words is "six hundred seventeen billion, one hundred forty-two million, five hundred eighty-four thousand, seven hundred fifty-three".