Base | Representation |
---|---|
bin | 11100000100011010000001… |
… | …00011010110100100100101 |
3 | 22002112202120201201101112220 |
4 | 32002031000203112210211 |
5 | 31042241332323121013 |
6 | 335135350225102553 |
7 | 16000262461341405 |
oct | 1602150043264445 |
9 | 262482521641486 |
10 | 61724058020133 |
11 | 18738031678263 |
12 | 6b0a652187a59 |
13 | 2859727616022 |
14 | 11356632a4805 |
15 | 7208b7523b23 |
hex | 3823408d6925 |
61724058020133 has 4 divisors (see below), whose sum is σ = 82298744026848. Its totient is φ = 41149372013420.
The previous prime is 61724058020101. The next prime is 61724058020189. The reversal of 61724058020133 is 33102085042716.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 61724058020133 - 25 = 61724058020101 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (61724058024133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10287343003353 + ... + 10287343003358.
It is an arithmetic number, because the mean of its divisors is an integer number (20574686006712).
Almost surely, 261724058020133 is an apocalyptic number.
It is an amenable number.
61724058020133 is a deficient number, since it is larger than the sum of its proper divisors (20574686006715).
61724058020133 is a wasteful number, since it uses less digits than its factorization.
61724058020133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20574686006714.
The product of its (nonzero) digits is 241920, while the sum is 42.
The spelling of 61724058020133 in words is "sixty-one trillion, seven hundred twenty-four billion, fifty-eight million, twenty thousand, one hundred thirty-three".
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