Base | Representation |
---|---|
bin | 101101010010000000101… |
… | …0101111010101111011111 |
3 | 211000221202112202101221012 |
4 | 1122210001111322233133 |
5 | 1303431041103303001 |
6 | 21123000534125435 |
7 | 1211425254216014 |
oct | 132440125725737 |
9 | 24027675671835 |
10 | 6223430134751 |
11 | 1a8a384080685 |
12 | 8461861b087b |
13 | 361b368a0b1b |
14 | 17730396970b |
15 | abd443842bb |
hex | 5a90157abdf |
6223430134751 has 8 divisors (see below), whose sum is σ = 6229721792064. Its totient is φ = 6217140326400.
The previous prime is 6223430134661. The next prime is 6223430134783. The reversal of 6223430134751 is 1574310343226.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 6223430134751 - 210 = 6223430133727 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 6223430134699 and 6223430134708.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (6223438134751) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6323231 + ... + 7240863.
It is an arithmetic number, because the mean of its divisors is an integer number (778715224008).
Almost surely, 26223430134751 is an apocalyptic number.
6223430134751 is a deficient number, since it is larger than the sum of its proper divisors (6291657313).
6223430134751 is a wasteful number, since it uses less digits than its factorization.
6223430134751 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 924481.
The product of its (nonzero) digits is 362880, while the sum is 41.
Adding to 6223430134751 its reverse (1574310343226), we get a palindrome (7797740477977).
The spelling of 6223430134751 in words is "six trillion, two hundred twenty-three billion, four hundred thirty million, one hundred thirty-four thousand, seven hundred fifty-one".
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