Base | Representation |
---|---|
bin | 101101010111001011010… |
… | …1001100001010110111001 |
3 | 211002000101202201122020212 |
4 | 1122232112221201112321 |
5 | 1304121301400412213 |
6 | 21132033512000505 |
7 | 1212300225144053 |
oct | 132562651412671 |
9 | 24060352648225 |
10 | 6234525013433 |
11 | 1a94057922202 |
12 | 848361990135 |
13 | 362bb4367bb2 |
14 | 177a772968d3 |
15 | ac2934159a8 |
hex | 5ab96a615b9 |
6234525013433 has 4 divisors (see below), whose sum is σ = 6262482524928. Its totient is φ = 6206567501940.
The previous prime is 6234525013421. The next prime is 6234525013463. The reversal of 6234525013433 is 3343105254326.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 6234525013433 - 212 = 6234525009337 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (6234525013463) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13978755413 + ... + 13978755858.
It is an arithmetic number, because the mean of its divisors is an integer number (1565620631232).
Almost surely, 26234525013433 is an apocalyptic number.
It is an amenable number.
6234525013433 is a deficient number, since it is larger than the sum of its proper divisors (27957511495).
6234525013433 is a wasteful number, since it uses less digits than its factorization.
6234525013433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 27957511494.
The product of its (nonzero) digits is 777600, while the sum is 41.
The spelling of 6234525013433 in words is "six trillion, two hundred thirty-four billion, five hundred twenty-five million, thirteen thousand, four hundred thirty-three".
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