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625381878133 is a prime number
BaseRepresentation
bin10010001100110111010…
…10100010100101110101
32012210012221100001121201
421012123222202211311
540221240230100013
61155144012012501
763116355153505
oct11063352424565
92183187301551
10625381878133
1122124a848291
12a1253161131
1346c8632b9cc
14223a9235a05
15114033243dd
hex919baa2975

625381878133 has 2 divisors, whose sum is σ = 625381878134. Its totient is φ = 625381878132.

The previous prime is 625381878089. The next prime is 625381878197. The reversal of 625381878133 is 331878183526.

625381878133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 618270835204 + 7111042929 = 786302^2 + 84327^2 .

It is a cyclic number.

It is not a de Polignac number, because 625381878133 - 213 = 625381869941 is a prime.

It is a super-2 number, since 2×6253818781332 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (625381875133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 312690939066 + 312690939067.

It is an arithmetic number, because the mean of its divisors is an integer number (312690939067).

Almost surely, 2625381878133 is an apocalyptic number.

It is an amenable number.

625381878133 is a deficient number, since it is larger than the sum of its proper divisors (1).

625381878133 is an equidigital number, since it uses as much as digits as its factorization.

625381878133 is an evil number, because the sum of its binary digits is even.

The product of its digits is 5806080, while the sum is 55.

The spelling of 625381878133 in words is "six hundred twenty-five billion, three hundred eighty-one million, eight hundred seventy-eight thousand, one hundred thirty-three".