Base | Representation |
---|---|
bin | 101101110101110010010… |
… | …0011010010110100010101 |
3 | 211022022001201010210201222 |
4 | 1123223210203102310111 |
5 | 1311210411131411201 |
6 | 21222144202100125 |
7 | 1220115141523652 |
oct | 133534443226425 |
9 | 24268051123658 |
10 | 6300256513301 |
11 | 2009a18610a13 |
12 | 8590471aa645 |
13 | 36915b37190a |
14 | 17ad11024c29 |
15 | add3de1591b |
hex | 5bae48d2d15 |
6300256513301 has 4 divisors (see below), whose sum is σ = 6394290192672. Its totient is φ = 6206222833932.
The previous prime is 6300256513289. The next prime is 6300256513303. The reversal of 6300256513301 is 1033156520036.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-6300256513301 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (6300256513303) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47016839585 + ... + 47016839718.
It is an arithmetic number, because the mean of its divisors is an integer number (1598572548168).
Almost surely, 26300256513301 is an apocalyptic number.
It is an amenable number.
6300256513301 is a deficient number, since it is larger than the sum of its proper divisors (94033679371).
6300256513301 is an equidigital number, since it uses as much as digits as its factorization.
6300256513301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 94033679370.
The product of its (nonzero) digits is 48600, while the sum is 35.
The spelling of 6300256513301 in words is "six trillion, three hundred billion, two hundred fifty-six million, five hundred thirteen thousand, three hundred one".
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