Base | Representation |
---|---|
bin | 11100101011000100011111… |
… | …00010101100000001011011 |
3 | 22021020202121002121210200001 |
4 | 32111202033202230001123 |
5 | 31231023034200443004 |
6 | 342033533114153431 |
7 | 16165252266136111 |
oct | 1625421742540133 |
9 | 267222532553601 |
10 | 63052528140379 |
11 | 190aa4773a5148 |
12 | 70a4004122877 |
13 | 2924a9bb50c5b |
14 | 117da89a17ab1 |
15 | 74521aac51a4 |
hex | 39588f8ac05b |
63052528140379 has 12 divisors (see below), whose sum is σ = 65929295728800. Its totient is φ = 60296326050224.
The previous prime is 63052528140377. The next prime is 63052528140409. The reversal of 63052528140379 is 97304182525036.
It is not a de Polignac number, because 63052528140379 - 21 = 63052528140377 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (63052528140377) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 12452644 + ... + 16768225.
It is an arithmetic number, because the mean of its divisors is an integer number (5494107977400).
It is a 1-persistent number, because it is pandigital, but 2⋅63052528140379 = 126105056280758 is not.
Almost surely, 263052528140379 is an apocalyptic number.
63052528140379 is a deficient number, since it is larger than the sum of its proper divisors (2876767588421).
63052528140379 is a wasteful number, since it uses less digits than its factorization.
63052528140379 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 29224994 (or 29224971 counting only the distinct ones).
The product of its (nonzero) digits is 10886400, while the sum is 55.
The spelling of 63052528140379 in words is "sixty-three trillion, fifty-two billion, five hundred twenty-eight million, one hundred forty thousand, three hundred seventy-nine".
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