Base | Representation |
---|---|
bin | 101101111101101100001… |
… | …1011111000001111110010 |
3 | 211100220212211121101011121 |
4 | 1123323120123320033302 |
5 | 1312000143134041200 |
6 | 21234032525332454 |
7 | 1221255632321650 |
oct | 133733033701762 |
9 | 24326784541147 |
10 | 6317233112050 |
11 | 201613a446913 |
12 | 8603a470712a |
13 | 36a935560713 |
14 | 17ba81971dd0 |
15 | ae4d4518e1a |
hex | 5bed86f83f2 |
6317233112050 has 48 divisors (see below), whose sum is σ = 13714348296960. Its totient is φ = 2119825330560.
The previous prime is 6317233111967. The next prime is 6317233112053. The reversal of 6317233112050 is 502113327136.
It is a junction number, because it is equal to n+sod(n) for n = 6317233111997 and 6317233112015.
It is not an unprimeable number, because it can be changed into a prime (6317233112053) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 191996715 + ... + 192029614.
It is an arithmetic number, because the mean of its divisors is an integer number (285715589520).
Almost surely, 26317233112050 is an apocalyptic number.
6317233112050 is an abundant number, since it is smaller than the sum of its proper divisors (7397115184910).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
6317233112050 is a wasteful number, since it uses less digits than its factorization.
6317233112050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 384026395 (or 384026390 counting only the distinct ones).
The product of its (nonzero) digits is 22680, while the sum is 34.
Adding to 6317233112050 its reverse (502113327136), we get a palindrome (6819346439186).
The spelling of 6317233112050 in words is "six trillion, three hundred seventeen billion, two hundred thirty-three million, one hundred twelve thousand, fifty".
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