Base | Representation |
---|---|
bin | 111010110111100100… |
… | …001101010100011101 |
3 | 20001011011101022220011 |
4 | 322313210031110131 |
5 | 2013423032430123 |
6 | 45012105523221 |
7 | 4365245611501 |
oct | 726744152435 |
9 | 201134338804 |
10 | 63209264413 |
11 | 24896a889a9 |
12 | 103007a3511 |
13 | 5c645c0809 |
14 | 30b8bb0301 |
15 | 199e380e0d |
hex | eb790d51d |
63209264413 has 2 divisors, whose sum is σ = 63209264414. Its totient is φ = 63209264412.
The previous prime is 63209264333. The next prime is 63209264441. The reversal of 63209264413 is 31446290236.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 37472442084 + 25736822329 = 193578^2 + 160427^2 .
It is a cyclic number.
It is not a de Polignac number, because 63209264413 - 217 = 63209133341 is a prime.
It is a super-2 number, since 2×632092644132 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (63209264513) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 31604632206 + 31604632207.
It is an arithmetic number, because the mean of its divisors is an integer number (31604632207).
Almost surely, 263209264413 is an apocalyptic number.
It is an amenable number.
63209264413 is a deficient number, since it is larger than the sum of its proper divisors (1).
63209264413 is an equidigital number, since it uses as much as digits as its factorization.
63209264413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 186624, while the sum is 40.
The spelling of 63209264413 in words is "sixty-three billion, two hundred nine million, two hundred sixty-four thousand, four hundred thirteen".
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