Base | Representation |
---|---|
bin | 11100110000111100011000… |
… | …11110110011111110100111 |
3 | 22021222001111201201111000001 |
4 | 32120132030132303332213 |
5 | 31242324342101140110 |
6 | 342310350500202131 |
7 | 16215655342620043 |
oct | 1630361436637647 |
9 | 267861451644001 |
10 | 63254340255655 |
11 | 1917801904537a |
12 | 7117146699347 |
13 | 293ab21712793 |
14 | 1189752647023 |
15 | 74a5cd19763a |
hex | 39878c7b3fa7 |
63254340255655 has 32 divisors (see below), whose sum is σ = 76539395899008. Its totient is φ = 50181474969600.
The previous prime is 63254340255637. The next prime is 63254340255661. The reversal of 63254340255655 is 55655204345236.
It is not a de Polignac number, because 63254340255655 - 231 = 63252192772007 is a prime.
It is a super-2 number, since 2×632543402556552 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 63254340255596 and 63254340255605.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 7138505925 + ... + 7138514785.
It is an arithmetic number, because the mean of its divisors is an integer number (2391856121844).
Almost surely, 263254340255655 is an apocalyptic number.
63254340255655 is a deficient number, since it is larger than the sum of its proper divisors (13285055643353).
63254340255655 is a wasteful number, since it uses less digits than its factorization.
63254340255655 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18747.
The product of its (nonzero) digits is 64800000, while the sum is 55.
The spelling of 63254340255655 in words is "sixty-three trillion, two hundred fifty-four billion, three hundred forty million, two hundred fifty-five thousand, six hundred fifty-five".
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