Base | Representation |
---|---|
bin | 1000111111110100100111100… |
… | …0000111000001101100001101 |
3 | 10002000200222111111102022002001 |
4 | 2033331021320013001230031 |
5 | 1130441042144404224323 |
6 | 10122312431315032301 |
7 | 250233431503511425 |
oct | 21775117007015415 |
9 | 3060628444368061 |
10 | 633123144211213 |
11 | 17380702146a257 |
12 | 5b01360bb9b691 |
13 | 2123734419a726 |
14 | b24b47627d485 |
15 | 4d2debc71e3ad |
hex | 23fd2781c1b0d |
633123144211213 has 8 divisors (see below), whose sum is σ = 635377098097080. Its totient is φ = 630869196330240.
The previous prime is 633123144211163. The next prime is 633123144211241. The reversal of 633123144211213 is 312112441321336.
633123144211213 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 4 ways, for example, as 234430793743689 + 398692350467524 = 15311133^2 + 19967282^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 633123144211213 - 213 = 633123144203021 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (633123144211913) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 417688731 + ... + 419201767.
It is an arithmetic number, because the mean of its divisors is an integer number (79422137262135).
Almost surely, 2633123144211213 is an apocalyptic number.
It is an amenable number.
633123144211213 is a deficient number, since it is larger than the sum of its proper divisors (2253953885867).
633123144211213 is a wasteful number, since it uses less digits than its factorization.
633123144211213 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3002447.
The product of its digits is 62208, while the sum is 37.
Adding to 633123144211213 its reverse (312112441321336), we get a palindrome (945235585532549).
The spelling of 633123144211213 in words is "six hundred thirty-three trillion, one hundred twenty-three billion, one hundred forty-four million, two hundred eleven thousand, two hundred thirteen".
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