Base | Representation |
---|---|
bin | 111010111110110110… |
… | …000100111101001001 |
3 | 20001110200011220200112 |
4 | 322332312010331021 |
5 | 2014200313424012 |
6 | 45032151244105 |
7 | 4401260632553 |
oct | 727666047511 |
9 | 201420156615 |
10 | 63331389257 |
11 | 24949a11124 |
12 | 10335679635 |
13 | 5c839ac936 |
14 | 30cb0c04d3 |
15 | 19a9e56122 |
hex | ebed84f49 |
63331389257 has 2 divisors, whose sum is σ = 63331389258. Its totient is φ = 63331389256.
The previous prime is 63331389217. The next prime is 63331389259. The reversal of 63331389257 is 75298313336.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 61648420681 + 1682968576 = 248291^2 + 41024^2 .
It is a cyclic number.
It is not a de Polignac number, because 63331389257 - 210 = 63331388233 is a prime.
Together with 63331389259, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (63331389259) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 31665694628 + 31665694629.
It is an arithmetic number, because the mean of its divisors is an integer number (31665694629).
Almost surely, 263331389257 is an apocalyptic number.
It is an amenable number.
63331389257 is a deficient number, since it is larger than the sum of its proper divisors (1).
63331389257 is an equidigital number, since it uses as much as digits as its factorization.
63331389257 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2449440, while the sum is 50.
The spelling of 63331389257 in words is "sixty-three billion, three hundred thirty-one million, three hundred eighty-nine thousand, two hundred fifty-seven".
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